Chemistry · Electrochemistry

Potassium chlorate is prepared by electrolysis of KCl in basic solution as shown by the following equation: 6OH- + Cl- → ClO3- + 3H2O + 6e- A current of x A has to be passed for 10 h to produce 10.0 g of potassium chlorate. The value of x is (Nearest integer): (Molar mass of KClO3 = 122.6 g mol-1, F = 96500 C mol-1)

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