Mathematics · Problems on Ages
Nine years ago, a father was nine times as old as his son, and ten years hence, he will be two years more than twice the age of his son then. What are their present ages?
- 1Father = 36 yr, Son = 12 yr✓
- 2Father = 34 yr, Son = 11 yr
- 3Father = 33 yr, Son = 10 yr
- 4Father = 32 yr, Son = 9 yr
Correct answer
Father = 36 yr, Son = 12 yr
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