Chemistry · Organic Chemistry
Methyl propanoate on hydrolysis with dilute NaOH forms a sodium salt, which on further acidification with concentrated HCl forms which of the following carboxylic acids?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1CH3CH2COOH✓
- 2CH3COOH
- 3HCOOH
- 4CH3CH2CH2COOH
Correct answer
CH3CH2COOH
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