Physics · Thermodynamics - Internal Energy Changes
Match the thermodynamic processes in List-I with the corresponding magnitude of change in internal energy |ΔU| (in kJ) in List-II: List-I (I) 2 × 10-3 kg of water at 100°C is converted into steam at 100°C and pressure 105 Pa. (Latent heat = 2000 kJ/kg, volume change = 10-3 m3) (II) 1 mole of a diatomic ideal gas at 300 K undergoes isobaric expansion from volume V to 2V. (III) 1 mole of a monoatomic ideal gas with P1V1 = 2 kJ is compressed adiabatically from volume V to V/4. (IV) 2 moles of a diatomic ideal gas (vibrational modes active, Cp = 4R, Cv = 3R) are supplied 8 kJ of heat in an isobaric process. List-II (P) 3.9 ≈ 4 kJ (Q) 5 kJ (R) 6 kJ (S) 6.23 ≈ 6 kJ (or 3.1 ≈ 3 kJ) (T) 7 kJ
- 1I→P, II→Q, III→S, IV→T
- 2I→Q, II→P, III→R, IV→S
- 3I→P, II→S, III→Q, IV→R✓
- 4I→P, II→Q, III→T, IV→S
Correct answer
I→P, II→S, III→Q, IV→R
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