Chemistry · Electrochemistry
Match the Chemical Conversion (List I) with the correct Number of Faraday required (List II): List I (Chemical Conversion) A. Reduction of 1 mol of Cu2+ to Cu(s) B. Oxidation of 1 mol of Cl- to Cl2(g) C. Reduction of 2 mol of Al3+ to Al(s) D. Oxidation of 1 mol of Fe2+ to Fe3+ List II (Number of Faraday required) I. 1 F II. 2 F III. 6 F IV. 1 F
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1A-II, B-I, C-IV, D-II
- 2A-II, B-I, C-III, D-I✓
- 3A-I, B-III, C-IV, D-I
- 4A-III, B-I, C-IV, D-I
Correct answer
A-II, B-I, C-III, D-I
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