Mathematics · Definite Integrals
limn→∞ [ n+1n2+12 + n+2n2+22 + n+3n2+32 + ... + n+2nn2+4n2 ] =
- 1tan-12 + 12 log 3
- 2π4 + 12 log 3
- 3tan-12 + 12 log 5
- 4π4 + 12 log 5✓
Correct answer
π4 + 12 log 5
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