Mathematics · Geometry
Let ΔABC be an isosceles triangle such that AB and AC are of equal length. AD is the altitude from A on BC and BE is the altitude from B on AC. If AD and BE intersect at O such that °AOB = 105°, then ADBE equals:
- 1cos 15°
- 22 sin 15°
- 3sin 15°
- 42 cos 15°✓
Correct answer
2 cos 15°
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