Mathematics · Differential Equations
Let y(x) be the solution of the differential equation 2x2dy + (ey − 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to:
- 1loge(e2)
- 2loge(2)
- 3loge(e)
- 4loge(2e)✓
Correct answer
loge(2e)
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