Mathematics · Partial Differential Equations
Let u(x, y) be the solution of ∂2u∂x2 + ∂2u∂y2 = 64 in the unit disc {(x, y) | x2 + y2 < 1} such that u vanishes on the boundary of the disc. Then the value of u(1/4, 1/√2) is equal to:
- 1-16
- 2-7✓
- 316
- 47
Correct answer
-7
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