Let the probability mass function of X be given by p(x) = 18/38 for x = 0.5; p(x) = 18/38 for x = 1; p(x) = 2/38 for x = 10; and p(x) = 0 otherwise. Then P(0 ≤ X ≤ 2) is equal to:

The mean and standard deviation of a Binomial distribution with parameters n, p, and q (where q = 1 - p) are respectively:

In a Binomial Distribution, the formula for calculating the standard deviation is:

Given below are two statements: Statement I: The F-distribution is defined as the ratio of two independent chi-square random variables, each divided by its respective degrees of freedom. Statement II: The Student's t-distribution is symmetric about the origin (mean = 0) with a bell shape similar to the standard normal distribution.