Mathematics · Relations and Functions
Let R = {(P, Q) | P and Q are at the same distance from the origin} be an equivalence relation on a plane. Then, the equivalence class of the point (1, -1) is given by the set:
- 1S = { (x, y) | x2 + y2 = 4 }
- 2S = { (x, y) | x2 + y2 = √2 }
- 3S = { (x, y) | x2 + y2 = 2 }✓
- 4S = { (x, y) | x2 + y2 = 1 }
Correct answer
S = { (x, y) | x2 + y2 = 2 }
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