Mathematics · Functions
Let R be the set of all real numbers and a function f : R → R be defined by f(x) = ax + b, where a, b are constants and a ≠ 0. Is f invertible? If so, find the inverse of f.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1f is onto but not one-to-one
- 2The inverse of f does not exist
- 3f is one-to-one but not onto
- 4Inverse of f exists and f-1(x) = x - ba✓
Correct answer
Inverse of f exists and f-1(x) = x - ba
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