Mathematics · Circle
Let PQ and MN be two straight lines touching the circle x2 + y2 - 4x - 6y - 3 = 0 at the points A and B respectively. Let O be the centre of the circle and ∠AOB = π/3. Then the locus of the point of intersection of the lines PQ and MN is:
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- 13(x2 + y2) - 12x - 18y - 25 = 0✓
- 2x2 + y2 - 18x - 12y - 25 = 0
- 3x2 + y2 - 12x - 18y - 25 = 0
- 43(x2 + y2) - 18x - 12y + 25 = 0
Correct answer
3(x2 + y2) - 12x - 18y - 25 = 0
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