Mathematics · Definite Integration and Limits
Let f be a non-negative function defined on [0,1] and twice differentiable in (0,1). If ∫0x √(1 - (f'(t))2) dt = ∫0x f(t) dt for all 0 ≤ x ≤ 1 and f(0) = 0, then limx → 0 1x2 ∫0x f(t) dt:
- 1equals 12✓
- 2equals 1
- 3equals 0
- 4does not exist
Correct answer
equals 12
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