Mathematics · Permutations and Combinations

Let C(n, r) = nCr. The value of 20∑ k=0 (2k + 1) C(41, 2k + 1) is:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

141 × 239
241 × 240✓
340 × 239
440 × 240

Correct answer

41 × 240

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Let C(n, r) = nCr. The value of 20∑ k=0 (2k + 1) C(41, 2k + 1) is:

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Let C(n, r) = nCr. The value of 20∑ k=0 (2k + 1) C(41, 2k + 1) is:

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