Mathematics · Geometric Progression

Let a1, a22, a322, ..., a1029 be a G.P. of common ratio 1√2. If a1 + a2 + ... + a10 = 62, then a1 is equal to:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

12(√2 + 1)
2√2 - 1
32 - √2
42(√2 - 1)✓

Correct answer

2(√2 - 1)

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Let a1, a22, a322, ..., a1029 be a G.P. of common ratio 1√2. If a1 + a2 + ... + a10 = 62, then a1 is equal to:

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Let a1, a22, a322, ..., a1029 be a G.P. of common ratio 1√2. If a1 + a2 + ... + a10 = 62, then a1 is equal to:

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