Mathematics · Progression - Arithmetic Progression
Let a1, a2, a3, ... be an Arithmetic Progression (A.P.). If a1 + a2 + ... + a10a1 + a2 + ... + ap = 100p2 where p ≠ 10, then a11a10 is equal to:
- 1121100
- 22119✓
- 3100121
- 41921
Correct answer
2119
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