Mathematics · Quadratic Equations
Let a, b ∈ R, a ≠ 0 be such that the equation, ax2 - 2bx + 5 = 0 has a repeated root α, which is also a root of the equation, x2 - 2bx - 10 = 0. If β is the other root of this equation, then a2 + β2 is equal to:
- 124
- 228
- 326
- 425✓
Correct answer
25
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