Mathematics · Coordinate Geometry
Let A(a, 0), B(b, 2b + 1) and C(0, b), where b ≠ 0 and |b| ≠ 1, be points such that the area of triangle ABC is 1 sq. unit. Then the sum of all possible values of a is:
- 12bb + 1
- 2-2b2b + 1✓
- 32b2b + 1
- 4-2bb + 1
Correct answer
-2b2b + 1
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