Mathematics · Trigonometry

Let 0° < θ < 90°. The expression √( sec 2 θ + cosec 2 θ tan 2 θ - sin 2 θ ) × (1 + tan 2 θ) sin 2 θ (cosecθ - cotθ)(1 + cosθ) is equal to:

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Correct answer

cosec 2 θ sec 2 θ

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Let 0&deg; < &theta; < 90&deg;. The expression &radic;( sec 2 &theta; + cosec 2 &theta; tan 2 &theta; - sin 2 &theta; ) &times; (1 + tan 2 &theta;) sin 2 &theta; (cosec&theta; - cot&theta;)(1 + cos&theta;) is equal to: