Mathematics · Quadratic Equations
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option. I. 4x2 - (72 ÷ 2)x + 132 = 3x2 + 1 - 10x II. y2 + 270 = 33y
- 1x ≥ y
- 2x = y or the relationship cannot be established
- 3x < y✓
- 4x > y
Correct answer
x < y
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