Mathematics · Permutations and Combinations
In how many ways can a student choose (n - 2) courses out of n courses if 2 specific courses are compulsory (where n > 4)?
- 1(n - 2)(n - 3)/2✓
- 2(n - 3)(n - 4)/2
- 3(n - 1)(n - 2)
- 4(n - 3)(n - 4)
Correct answer
(n - 2)(n - 3)/2
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