Mathematics · Mensuration
In an isosceles trapezium ABCD, AD is parallel to BC. The lengths are given as CD = 17 cm, BM = 8 cm (where AM is perpendicular to BC), and BC = 36 cm. If the trapezium is divided into a shaded portion (trapezium AMCD) and a non-shaded portion (triangle ABM), find the difference between the perimeters of the shaded and non-shaded portions.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 140 cm
- 230 cm
- 320 cm
- 410 cm✓
Correct answer
10 cm
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Mathematics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Mensuration MCQs →Want more practice questions on Mensuration?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Mensuration