Mathematics · Network Analysis
In a two-loop circuit, Loop 1 has a 36 V source and a 3 Ω resistor, and Loop 2 has a 24 V source and a 4 Ω resistor. Both loops share a common branch containing a 12 Ω resistor. Applying Kirchhoff's Voltage Law (KVL) yields the loop equations: 36 - 3I 1 - 12(I 1 - I 2 ) = 0 24 - 4I 2 - 12(I 2 - I 1 ) = 0 Find the current flowing through the shared 12 Ω resistor.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 10.75 A✓
- 21 A
- 33 A
- 40.25 A
Correct answer
0.75 A
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Mathematics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Network Analysis MCQs →Want more practice questions on Network Analysis?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Network Analysis