Physics · Electromagnetic Induction
In a rectangular conducting loop PQRS, the conductor segment PQ of length l is free to move. When PQ is moved towards the left with a constant velocity V in a perpendicular magnetic field B, what will be the magnetic flux linked with the loop (where x is the width of the loop at that instant) and the magnitude of the motional emf?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Magnetic flux = B l (x V); Motional emf = B l x
- 2Magnetic flux = B l x; Motional emf = (B l V) / t
- 3Magnetic flux = B l x; Motional emf = B l V✓
- 4Magnetic flux = B / (l x); Motional emf = B l V
Correct answer
Magnetic flux = B l x; Motional emf = B l V
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