Mathematics · Vector Algebra
In a quadrilateral ABCD, the angle ∠A = 2π3 and AC is the internal bisector of angle ∠A. If 15|AC| = 5|AD| = 3|AB|, then the cosine of the angle between AB and BC is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1cos -1 ( 4√3 5√7 )
- 2cos -1 ( 3√3 2√7 )✓
- 3cos -1 ( 3√3 4√7 )
- 4cos -1 ( √3 √7 )
Correct answer
cos -1 ( 3√3 2√7 )
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