Physics · Classical Mechanics
In a fixed target elastic scattering experiment, a projectile of mass m, having initial velocity v0 and impact parameter b, approaches the scatterer. It experiences a central repulsive force f(r) = kr3 (k > 0). What is the distance of the closest approach d?
- 1d = (b2 + km v02)12✓
- 2d = (b2 - km v02)12
- 3d = b
- 4d = √km v02
Correct answer
d = (b2 + km v02)12
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