Physics · Wave Optics
In a double slit experiment, the distance between the slits is 0.1 cm and the screen is placed 50 cm from the slit plane. When one slit is covered with a transparent sheet of thickness t and refractive index n = 1.5, the central fringe shifts by 0.2 cm. The value of t is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 15.0 × 10-3 cm
- 25.6 × 10-4 cm
- 36.0 × 10-3 cm
- 48 × 10-4 cm✓
Correct answer
8 × 10-4 cm
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