In a circuit, a capacitor C1 is initially charged to a total charge Q by a battery of EMF E with key K1 closed and key K2 open. Then K1 is opened and K2 is closed to connect C1 in parallel with an uncharged capacitor C2. If Q1' and Q2' represent the final steady-state charges on C1 and C2 respectively, then:

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Physics · Electrostatic Potential and Capacitance

Verified Solution4 OptionsUpdated: October 2026👁️1 View

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charge on C1 gets redistributed such that Q1' + Q2' = Q.

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Answer 1

charge on C1 gets redistributed such that Q1' + Q2' = Q.

Answer 2

charge on C1 gets redistributed such that C1V1 + C2V2 = 2C1E.

Answer 3

charge on C1 gets redistributed such that Q1' = Q2' always.

Answer 4

charge on C1 gets redistributed such that the final voltages satisfy V1 = 2V2.

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