Mathematics · Differential Equations
If y1(x) = x is a solution of (1 - x)y'' + xy' - y = 0, x > 1, then what is its general solution?
- 1y(x) = c1 x + c2 (x - 1)
- 2y(x) = c1 x + c2 x2
- 3y(x) = c1 x + c2 x-1 ex
- 4y(x) = c1 x + c2 ex✓
Correct answer
y(x) = c1 x + c2 ex
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