Mathematics · Differential Equations
If y1(x) is a non-trivial solution of the linear differential equation dydx + f(x)y = 0, then the general solution of the non-homogeneous equation dydx + f(x)y = r(x) is given by:
- 1y = ∫ r(x)y1(x) dx
- 2y = y1(x) ∫ r(x)y1(x) dx✓
- 3y = y1(x) ∫ r(x)y1(x) dx
- 4y = y1(x) ∫ r(x) dx
Correct answer
y = y1(x) ∫ r(x)y1(x) dx
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