Mathematics · Differential Calculus
If y = √(x + √(y + √(x + √(y + ... ∞)))), then dydx is equal to:
- 1y2 - x2y3 - 2xy - 1✓
- 22y2 - 2xy + 1
- 33y3 - 2xy2 + xy + 2
- 4y3x - y
Correct answer
y2 - x2y3 - 2xy - 1
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