Mathematics · Ordinary Differential Equations
If y = x is a solution of the ordinary differential equation (ODE) d2ydx2 - ( 2x2 + 1x )( x dydx - y ) = 0, for 0 < x < ∞, then the general solution of the ODE is given by:
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- 1(a + b ex)x, where a, b ∈ R✓
- 2a ex + b x, where a, b ∈ R
- 3(a + b e2x)x, where a, b ∈ R
- 4(a + b e-2x)x, where a, b ∈ R
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(a + b ex)x, where a, b ∈ R
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