Mathematics · Calculus
If y = (logx sin x)x, then what is the value of dydx?
- 1y [ x cot xlog sin x - log(log sin x) + 1log x - log x ]
- 2y [ x cot xlog sin x + log(log sin x) - 1log x - log(log x) ]✓
- 3y [ x cos xlog sin x - log(log sin x) + 1log x + log(log x) ]
- 4y [ x sin xlog cos x + log(log sin x) + 1log x - log(log x) ]
Correct answer
y [ x cot xlog sin x + log(log sin x) - 1log x - log(log x) ]
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