Mathematics · Differential Equations
If x dy + (y + y2x) dx = 0 and y = 1 at x = 1, then the solution is:
- 1y = x1 + log x
- 2y = 1 + log xx
- 3y = x(1 + log x)
- 4y = 1x(1 + log x)✓
Correct answer
y = 1x(1 + log x)
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