Mathematics · Vector Calculus
If vec(A) = ax i + by j + cz k where a, b, c are constants, then &iint;S vec(A) · dvec(S), where S is the surface of a unit sphere, is equal to:
- 143π(a2+b2+c2)
- 20
- 343π(a+b+c)✓
- 443π(a+b+c)2
Correct answer
43π(a+b+c)
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