Mathematics · Partial Differentiation
If u = exyz, then ∂3u∂x ∂y ∂z is equal to:
- 1u[1 + 2xyz + x2y2z2]
- 2u[1 + 3xyz + 2x2y2z2]
- 3u[1 + 3xyz + x2y2z2]✓
- 4u[3xyz + x2y2z2]
Correct answer
u[1 + 3xyz + x2y2z2]
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