Mathematics · Conic Sections
If the eccentricity of the hyperbola x2a2 - y2b2 = 1 passing through the point (4, 6) is 2, then the equation of the tangent to this hyperbola at (4, 6) is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 12x - 3y + 10 = 0
- 23x - 2y = 0
- 3x - 2y + 8 = 0
- 42x - y - 2 = 0✓
Correct answer
2x - y - 2 = 0
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