Physics · Simple Harmonic Motion
If the displacement y (in cm) of a particle executing simple harmonic motion is given by the equation y = 5 sin(3πt) + 5√3 cos(3πt), then the amplitude of the particle is:
- 110 cm✓
- 25(1 + √3) cm
- 35√3 cm
- 45 cm
Correct answer
10 cm
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