Mathematics · Network Analysis
If the current through a series RL circuit connected to a 5 Ω resistor is i(t) = 3 + 4 sin(200t + 45°) + 4 sin(300t + 60°) A, the RMS value of this current and the total power dissipated in the circuit are __________, respectively.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1√41 A and 125 W
- 211 A and 250 W
- 35 A and 125 W✓
- 4√41 A and 250 W
Correct answer
5 A and 125 W
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