Mathematics · Integral Calculus

If I1 = ∫ [ex / (ex + e-x)] dx and I2 = ∫ [1 / (e2x + 1)] dx, then what is I1 + I2 equal to?

Verified Solution4 OptionsUpdated: October 2026👁️1 View

1ln(ex - e-x) + c
2ln(ex + e-x) + c
3x + c✓
4x/2 + c

Correct answer

x + c

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If I1 = ∫ [ex / (ex + e-x)] dx and I2 = ∫ [1 / (e2x + 1)] dx, then what is I1 + I2 equal to?

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If I1 = ∫ [ex / (ex + e-x)] dx and I2 = ∫ [1 / (e2x + 1)] dx, then what is I1 + I2 equal to?

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