Mathematics · Integration
If I = ∫ exe4x + e2x + 1 dx and J = ∫ e-xe-4x + e-2x + 1 dx, then for any arbitrary constant C, the value of J - I equals:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 112 log |e4x - e2x + 1e4x - e2x + 1| + C
- 212 log |e2x - ex + 1e2x + ex + 1| + C✓
- 312 log |e2x + ex + 1e2x - ex + 1| + C
- 412 log |e4x - e2x + 1e4x + e2x + 1| + C
Correct answer
12 log |e2x - ex + 1e2x + ex + 1| + C
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