Mathematics · Continuity and Differentiability
If f(x) = ⌈ 1-xm1-x, if x ≠ 1 ⌊ 2m-1, if x = 1 and the function is discontinuous at x = 1, then:
- 1m ≠ 1✓
- 2m = 12
- 3m ≠ 12
- 4m = 1
Correct answer
m ≠ 1
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