Mathematics · Integration

If ∫(e2x + 2ex - e-x - 1)e(ex + e-x) dx = g(x)e(ex + e-x) + c, where c is a constant of integration, then g(0) is:

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1e
2e2
31
42✓

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If ∫(e2x + 2ex - e-x - 1)e(ex + e-x) dx = g(x)e(ex + e-x) + c, where c is a constant of integration, then g(0) is:

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If ∫(e2x + 2ex - e-x - 1)e(ex + e-x) dx = g(x)e(ex + e-x) + c, where c is a constant of integration, then g(0) is:

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