Mathematics · Progressions
If a1, a2, ... are in A.P., then 1√a1 + √a2 + 1√a2 + √a3 + ... + 1√an + √an+1 is equal to:
- 1n - 1√a1 + √an+1
- 2n√a1 + √an+1✓
- 3n - 1√a1 + √an
- 4n√a1 - √an+1
Correct answer
n√a1 + √an+1
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