Mathematics · Indefinite Integrals
If ∫3ex - 5e-x4ex + 5e-xdx = ax + b log|4ex + 5e-x| + C, then the values of a and b are:
- 1a = 18, b = -78
- 2a = -18, b = -78
- 3a = 18, b = 78
- 4a = -18, b = 78✓
Correct answer
a = -18, b = 78
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