Mathematics · Differentiation

If 2x = y 1/5 + y -1/5 and (x 2 - 1) d 2 y dx 2 + λ x dy dx + ky = 0, then the value of λ + k is:

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If 2x = y 1/5 + y -1/5 and (x 2 - 1) d 2 y dx 2 + λ x dy dx + ky = 0, then the value of λ + k is:

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If 2x = y 1/5 + y -1/5 and (x 2 - 1) d 2 y dx 2 + &lambda; x dy dx + ky = 0, then the value of &lambda; + k is:

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If 2x = y 1/5 + y -1/5 and (x 2 - 1) d 2 y dx 2 + λ x dy dx + ky = 0, then the value of λ + k is: