Mathematics · Indefinite Integrals
If ∫ 1cot(x/2) cot(x/3) cot(x/6) dx = A log|cos(x/2)| + B log|cos(x/3)| + C log|cos(x/6)| + k, then A + B + C =
- 11
- 2-7✓
- 311
- 47
Correct answer
-7
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