Mathematics · Definite Integrals
If ∫01 et1 + t dt = a, then ∫01 et(1 + t)2 dt is equal to:
- 1a + 1 + e2
- 2a - 1 - e2
- 3a + 1 - e2✓
- 4a - 1 + e2
Correct answer
a + 1 - e2
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