Mathematics · Trigonometry

If 0 ≤ (α - β) ≤ (α + β) ≤ π 2 , tan(α + β) = √3 and tan(α - β) = 1 √3 , then what is tanα · cot(2β) equal to?

Verified Solution4 OptionsUpdated: October 2026👁️1 View

11
2√2
3√3✓
41 √3

Correct answer

√3

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If 0 ≤ (α - β) ≤ (α + β) ≤ π 2 , tan(α + β) = √3 and tan(α - β) = 1 √3 , then what is tanα · cot(2β) equal to?

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If 0 &le; (&alpha; - &beta;) &le; (&alpha; + &beta;) &le; &pi; 2 , tan(&alpha; + &beta;) = &radic;3 and tan(&alpha; - &beta;) = 1 &radic;3 , then what is tan&alpha; &middot; cot(2&beta;) equal to?

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If 0 ≤ (α - β) ≤ (α + β) ≤ π 2 , tan(α + β) = √3 and tan(α - β) = 1 √3 , then what is tanα · cot(2β) equal to?